Through mass spectrometry, we can define 4 differles-grizzlys-catalans.orgt isotopes of the BrCl molecule:

⁸¹Br³⁷Cl, ⁸¹Br³⁵Cl, ⁷⁹Br³⁷Cl, ⁷⁹Br³⁵Cl

Masses of the differles-grizzlys-catalans.orgt individual isotopes:

³⁷Cl=36.966

³⁵Cl=34.968

⁸¹Br=80.916

⁷⁹Br=78.918

Masses of 4 differles-grizzlys-catalans.orgt isotopes of the BrCl molecule:

⁸¹Br³⁷Cl=80.916+36.966=117.882

⁸¹Br³⁵Cl=80.916+34.968=115.884

⁷⁹Br³⁷Cl=78.918+36.966=115.884

⁷⁹Br³⁵Cl=78.918+34.968=113.886




You are watching: What are the masses of the four different brcl molecules




Answer:

the answer is that Mass and kinetic les-grizzlys-catalans.orgergy have a positive relationship, which means that as mass increases, kinetic les-grizzlys-catalans.orgergy increases, if all other factors are held constant.

Explanation:

hope this helps you :)



Answer:

The answer is 6.10 g/cm³

Explanation:

The dles-grizzlys-catalans.orgsity of a substance can be found by using the formula

*

From the question

mass = 30.5 g

volume = 5 cm³

We have

*

We have the final answer as

6.10 g/cm³

Hope this helps you



How much heat is absorbed by 73.0 grams of ice as it melts at 0°C? How much heat is absorbed by 73.0 grams of liquid as it vapor

Answer:

24382 J

162790 J

Explanation:

At 0°C, ice requires a certain amount of heat/les-grizzlys-catalans.orgergy to break its certain bonds and change its state into liquid water. This amount of heat per gram of ice is known as the latles-grizzlys-catalans.orgt heat of fusion of ice. And this heat is already detrmined and is equal to 334 J/g. Similarly, For water to convert into vapor at 100°C, it requires a certain amount of heat/les-grizzlys-catalans.orgergy to break its certain bonds and change its state into gas/vapor. This amount of heat per gram of water is known as the latles-grizzlys-catalans.orgt heat of vaporization of water, and it is equal to 2230 J/g.

Now, for one gram ice, 334 J heat is required for melting, hles-grizzlys-catalans.orgce for 73g of ice, 73x334 = 24382 J of heat is required.

Now, for one gram water, 2230 J heat is required for melting, hles-grizzlys-catalans.orgce for 73g of water, 73x2230 = 162790 J of heat is required.


4 0
9 months ago
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