Net Ionic Equations Are Important
|The reason to write a chemical equation is to express what we believe is actually happening in a chemical reaction.One of the most useful applications of the concept of principal speciesis in writing net ionic equations. These are equations that focus on the principal substances and ions involved in a reaction--the principal species--ignoring thosespectator ions that really don"t get involved. For example, consider the reaction described by the following full molecular equation: HCl(aq) + NaOH(aq) NaCl(aq) + H2OHCl, NaOH, and NaCl are all strong electrolytes. As such, they dissociate completely into their ions in solution, and although we might write "HCl" wereally mean "H+ + Cl". Similarly, "NaOH" is"Na+ + OH"and "NaCl" is"Na+ + Cl". (For more details on classifying electrolytes, click here.) H+(aq) + Cl(aq) + Na+(aq) + OH(aq) Na+(aq) + Cl(aq) + H2ONotice that Na+ and Cl never really react. They arefloating around at the beginning and still floating around at the end.Thus, a better equation for whatis actually happening would be just: H+(aq) + OH(aq) H2Owhere we have neglected the Na+ and Cl because theyare not really involved. If you want to emphasize that H+ is hydrated, then you can write: H3O+(aq) + OH(aq) 2 H2O|
Writing Net Ionic EquationsWriting net ionic equtaions is easier than you might think. First of all, we MUST start with an equation that includes the physical state:(s) for solid,(l) for liquid,(g) for gas, and(aq) for aqueous solution.The three rules for writing net ionic equations are really quite straightforward.Only consider breaking up the (aq) substances.Only break up strong electrolytes.Delete any ions that appear on both sides of the equation.Clearly rule 2 is the tricky one. You must know your strong electrolytes:
|strong acids||HCl, HBr, HI, HNO3, HClO3, HClO4, and H2SO4||strong bases||NaOH, KOH, LiOH, Ba(OH)2, and Ca(OH)2||salts||NaCl, KBr, MgCl2, and many, many more, all containing metals or NH4.|
Another ExampleHere"s another example: HF(aq) + AgNO3(aq) AgF(s) + HNO3(aq)Separating the aqueous strong electrolytes, we have: HF(aq) + Ag+(aq) + NO3(aq) AgF(s) + H+(aq) + NO3(aq)Note that HF is a weak acid, so we leave it together. Since AgF is a solid, weare saying that it precipitates from the reaction, and it wouldn"t be right to separate it into its ions. The spectator ion in this caseis NO3. It starts out in solution and ends upin solution as well, with no role in the actual reaction. We leave it out in writing the final net ionic equation: HF(aq) + Ag+(aq) AgF(s) + H+(aq)Again, if you want to emphasize that H+ is hydrated, then you can write: HF(aq) + Ag+(aq) + H2O AgF(s) + H3O+(aq)
What if I don"t have the products?In some situations you only know the reactants. For example, one might need to know the net ionc equation for "the reaction between NaHSO4 and NH3." What then?There are two ways to proceed:Determine the "molecular equation" and proceed as above. This works fine as long as you can figure out the product in the first place!
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Thus, H+ must be transferred from the HSO4 to the NH3. HSO4(aq) + NH3(aq) NH4+(aq) + SO42(aq)Quiz yourself on net ionic equations.