Factor the expression by grouping. First, the expression needs to be rewritten as x^2+ax+bx+6. To find a and b, set up a system to be solved.

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Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 6.

displaystylex^2-5x+6=left(x-2
ight)cdotleft(x-3
ight) Explanation: displaystylex^2-5x+6=left(x-2
ight)cdotleft(x-3
ight)

displaystyle4x^2-5x+6=left(2x-frac54-fracsqrt714i
ight)left(2x-frac54+fracsqrt714i
ight) Explanation:If the sign ...

x2-5x+1 Final result : x2 - 5x + 1 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-5x+1 The first term is, x2 its coefficient is 1 . The ...

x^2 - 5x +2 = (x - 2.5)^2 - 4.25 = (x - 2.5)^2 - (sqrt4.25)^2 = (x - 2.5)^2 + (sqrt4.5i)^2 Hence, it can be written as difference of squares and sum of square.

x2-5x+4 Final result : (x - 1) • (x - 4) Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-5x+4 The first term is, x2 its coefficient is ...

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Factor the expression by grouping. First, the expression needs to be rewritten as x^2+ax+bx+6. To find a and b, set up a system to be solved.

Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 6.

Quadratic polynomial can be factored using the transformation ax^2+bx+c=aleft(x-x_1
ight)left(x-x_2
ight), where x_1 and x_2 are the solutions of the quadratic equation ax^2+bx+c=0.

All equations of the form ax^2+bx+c=0 can be solved using the quadratic formula: frac-b±sqrtb^2-4ac2a. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

Factor the original expression using ax^2+bx+c=aleft(x-x_1
ight)left(x-x_2
ight). Substitute 3 for x_1 and 2 for x_2.

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Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

Two numbers r and s sum up to 5 exactly when the average of the two numbers is frac12*5 = frac52. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u.

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