At STP, potassium is classified as a solid specifically a metallic solid. At these conditions, the element is neither a molecular solid nor an ionic solid since both needs electron movement. Potassium exists in its metallic form. Hope this les-grizzlys-catalans.orgs the question.


You are watching: At stp potassium is classified as


les-grizzlys-catalans.org:

THE SPECIFIC HEAT OF ALUMINIUM IS 0.900 Jg^-1K^-1

Explanation:

To solve this question, follow the following steps listed below:

1. Write the formulae for heat change in a reaction

Heat = m c ΔT

2. Write out their values and convert to standard units.

m = mass of aluminum = 18.3g

Heat = 481 J

T2 = final temperature = 46.6°C = 273 + 46.6 = 319.6 K

T1 = initial temperature = 17.4 °C = 17.4 + 273 K = 290.4K

C = specific heat capacity of aluminum = ?

3. Solve for the specific heat of aluminium

c = Heat / m ΔT

c = 481 J / 18.3 g * ( 319.6 - 290.4) K

c = 481 / 18.3 * 29.2

c = 481 / 534.36

c = 0.900 Jg^-1K^-1

In conclusion, the specific heat capacity of aluminum is 0.900 Jg^-1K^-1.


8 0
3 months ago

Which of the following sets of descriptors matches the molecule below?
katovenus <111>
I think it is c hope this helps you out
8 0
8 months ago

Which is not a characteristic of all metals? Select one: a. soft and easy to cut b. Good electrical conductors c. Ductile and ma
sammy <17>
The les-grizzlys-catalans.org is option a.soft and easy to cutHope it helpsAnd if it does pls mark as brainliest
8 0
7 months ago

Which process produces the energy that is used by solar panels?
KengaRu <80>

les-grizzlys-catalans.org:

B

Explanation:


6 0
1 month ago
Read 2 more les-grizzlys-catalans.orgs

Using the relationship given in part 1, calculate Ecell if = 1.453 M and = 0.00176 M, assuming that the temperatur
gtnhenbr <62>

les-grizzlys-catalans.org:

1.05 V

Explanation:

Now recall Nernst equation;

Ecell= E°cell - 0.0592/n log /

Now we look at the values of E°cathode and E°anode

E°cathode= 0.34 V

E°anode = -0.74 V

E°cell= 0.34-(-0.74)

E°cell= 1.08 V

= 1.453 M

= 0.00176 M

n= 6

Ecell= E°cell - 0.0592/n log /

Ecell= 1.08 - 0.0592/6 × log<1.453>/<0.00176>

Ecell= 1.08 - 0.0592/6 × 2.917

Ecell= 1.08 - 0.02878

Ecell= 1.05 V


6 0
5 months ago
Other questions:
×
Add les-grizzlys-catalans.org
Send
×
Login
E-mail
Password
Remember me
Login
Not registered? Fast signup
×
Signup
Your nickname
E-mail
Password
Signup
close
Login Signup


See more: How Many Catalytic Converters Are In A Ford F150 : Complete Explanation

Ask question!